The wavelength of the {K_alpha} line for an e | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to Moseley's Law,the frequency $
u$ of the ${K_\alpha}$ line is given by $\sqrt{
u} = a(Z - b)$,where $Z$ is the atomic number and $b$

Vedclass · Accepted Answer

$4\lambda$

Vedclass · Answer

(C) According to Moseley's Law,the frequency $
u$ of the ${K_\alpha}$ line is given by $\sqrt{
u} = a(Z - b)$,where $Z$ is the atomic number and $b$ is the screening constant.Since $
u = \frac{c}{\lambda}$,we have $\frac{1}{\lambda} \propto (Z - b)^2$.For the first element,$Z_1 = 29$ and $\lambda_1 = \lambda$. For the second element,$Z_2 = 15$ and $\lambda_2 = ?$.Using the ratio: $\frac{\lambda_2}{\lambda_1} = \frac{(Z_1 - b)^2}{(Z_2 - b)^2}$.Substituting the values: $\frac{\lambda_2}{\lambda} = \frac{(29 - 1)^2}{(15 - 1)^2} = \frac{28^2}{14^2} = \left(\frac{28}{14}ight)^2 = 2^2 = 4$.Therefore,$\lambda_2 = 4\lambda$.

The wavelength of the ${K_\alpha}$ line for an element of atomic number $29$ is $\lambda$. Then the wavelength of the ${K_\alpha}$ line for an element of atomic number $15$ is (Take Moseley's constant $b = 1$ for both elements).

Similar Questions

If the wavelength of the $K_\alpha$ line of Molybdenum (atomic number $Z = 42$) is $0.7078\, \mathring A$,then the wavelength of the $K_\alpha$ line of Zinc (atomic number $Z = 30$) is .......

The maximum wavelength of hard $X$-rays required for the study of bone fractures is $10^{-11} \ m$. The accelerating voltage in the $X$-ray machine must be:

Calculate the wavelength of the $K_{\alpha}$ line for $Z=31$, given $a=5 \times 10^7 \text{ Hz}^{1/2}$ for a characteristic $X$-ray spectrum.

If the wavelength of the $K_\alpha$ line of an element with atomic number $43$ is $\lambda$,then the wavelength of the $K_\alpha$ line of an element with atomic number $29$ is:

The structure of solid crystals is investigated by using

Vedclass Test Series

Exam Paper Generator

Online Exam Module